Lecture 9
2025-07-29
Continuous Random Variables
From discrete jumps to smooth curves: modeling the continuous world
By the end of this lecture, you will be able to:
python
to work with continuous distributionsExamples: Dice rolls, number of emails, quiz scores
Examples: Height, weight, time, temperature
P(X = x) = 0
for Continuous Variables?For continuous random variables, the probability of any exact value is zero!
Think about it: What’s the probability someone is exactly 5.7324681… feet tall?
Instead, we ask:
P(5.7 ≤ X ≤ 5.8)?
P(X ≤ 6.0)?
P(X > 5.5)?
Key insight: We calculate probabilities for intervals, not exact points.
Click to see why P(X = exact value) = 0
🎯 Definition: The Probability Density Function (PDF) of a continuous random variable X is a function f(x) such that:
P(a \leq X \leq b) = \int_a^b f(x) \, dx
Properties of PDF:
Key Insight:
The area under the PDF curve between a and b gives the probability that X falls in that interval.
Probability = Area under curve: Select an interval to see probability
For continuous random variables, the CDF is:
F(x) = P(X \leq x) = \int_{-\infty}^x f(t) \, dt
Key relationship: f(x) = \frac{d}{dx}F(x)
The PDF is the derivative of the CDF!
Click anywhere to see F(x) = P(X ≤ x) for that point
Expected Value: E[X] = \mu = \int_{-\infty}^{\infty} x \cdot f(x) \, dx
Variance:
\text{Var}(X) = \sigma^2 = \int_{-\infty}^{\infty} (x - \mu)^2 f(x) \, dx = E[X^2] - (E[X])^2
Where:
E[X^2] = \int_{-\infty}^{\infty} x^2 \cdot f(x) \, dx
Important
Notice: Integrals replace sums when moving from discrete to continuous!
All values equally likely in an interval
Parameters: a (min), b (max)
PDF: f(x) = \frac{1}{b-a} for a \leq x \leq b
Mean: \frac{a+b}{2}
Variance: \frac{(b-a)^2}{12}
Use: Random numbers, waiting times
Bell-shaped, symmetric
Parameters: \mu (mean), \sigma^2 (variance)
PDF: f(x) = \frac{1}{\sigma\sqrt{2\pi}} e^{-\frac{(x-\mu)^2}{2\sigma^2}}
Mean: \mu
Variance: \sigma^2
Use: Heights, test scores, errors
Models waiting times
Parameters: \lambda (rate)
PDF: f(x) = \lambda e^{-\lambda x} for x \geq 0
Mean: \frac{1}{\lambda}
Variance: \frac{1}{\lambda^2}
Use: Time between events, lifetimes
Z = \frac{X - \mu}{\sigma}
A bus arrives uniformly between 10:00 AM and 10:20 AM. Let X = arrival time in minutes after 10:00 AM.
(a) What is the PDF of X?
(b) What’s the probability the bus arrives between 10:05 and 10:12?
(c) What’s the expected arrival time?
Solution. (a) X \sim \text{Uniform}(0, 20) f(x) = \frac{1}{20-0} = \frac{1}{20} \text{ for } 0 \leq x \leq 20
(b) P(5 \leq X \leq 12) = \int_5^{12} \frac{1}{20} dx = \frac{1}{20} \times (12-5) = \frac{7}{20} = 0.35
(c) E[X] = \frac{a+b}{2} = \frac{0+20}{2} = 10 minutes after 10:00 AM
Heights of adult women are normally distributed with μ = 64 inches and σ = 2.5 inches.
(a) What’s the probability a woman is taller than 67 inches?
(b) What height represents the 90th percentile?
(c) What’s the probability a woman is between 62 and 66 inches tall?
Solution. (a) P(X > 67) = P\left(Z > \frac{67-64}{2.5}\right) = P(Z > 1.2) = 1 - 0.8849 = 0.1151
(b) For 90th percentile: P(X \leq x) = 0.90
z_{0.90} = 1.28, so x = 64 + 1.28(2.5) = 67.2 inches
(c) P(62 \leq X \leq 66) = P\left(\frac{62-64}{2.5} \leq Z \leq \frac{66-64}{2.5}\right)
= P(-0.8 \leq Z \leq 0.8) = 0.7881 - 0.2119 = 0.5762
The time between customer arrivals at a store follows an exponential distribution with an average of 5 minutes between arrivals.
(a) What is the PDF?
(b) What’s the probability the next customer arrives within 3 minutes?
(c) What’s the probability no customer arrives in the next 10 minutes?
Solution. (a) Average = 5 minutes = \frac{1}{\lambda}, so \lambda = 0.2
f(x) = 0.2e^{-0.2x} \text{ for } x \geq 0
(b) P(X \leq 3) = \int_0^3 0.2e^{-0.2x} dx = 1 - e^{-0.2 \times 3} = 1 - e^{-0.6} = 0.4512
(c) P(X > 10) = e^{-0.2 \times 10} = e^{-2} = 0.1353
CLT in Action: Run simulation to see the magic!
If Y = aX + b, then:
Z = \frac{X - \mu}{\sigma} \sim N(0, 1)
Important: Normal distributions are closed under linear transformations!
Property | Discrete | Continuous |
---|---|---|
Probability Function | PMF: P(X = x) | PDF: f(x) |
Exact Value Probability | P(X = x) > 0 possible | P(X = x) = 0 always |
Interval Probability | \sum P(X = x_i) | \int_a^b f(x) dx |
Expected Value | \sum x \cdot P(X = x) | \int x \cdot f(x) dx |
Variance | \sum (x-\mu)^2 P(X = x) | \int (x-\mu)^2 f(x) dx |
CDF | \sum_{x_i \leq x} P(X = x_i) | \int_{-\infty}^x f(t) dt |
Memoryless Property (Exponential only):
P(X > s+t | X > s) = P(X > t)
Symmetry (Normal):
P(X \leq \mu - a) = P(X \geq \mu + a)
Scaling Invariance (Normal):
Linear combinations of normals are normal
Remember: Area under PDF = 1, but PDF values can exceed 1!
Choose distributions based on the data characteristics:
Topics we’ll cover:
Connection: Continuous distributions (especially normal) form the foundation for statistical inference
Office Hours: 11AM on Thursday (link on Canvas)
Email: nmathlouthi@ucsb.edu
Next Class: Statistical Inference and Hypothesis Testing
Understanding Data – Continuous Random Variables © 2025 Narjes Mathlouthi